Question

Find the roots of the quadratic equation x2 − 8x + 8 = 0 .

x1 = x2 =

Answer 1

\[(-b \pm \sqrt{b ^{2}-4ac)}/2a\]

Answer 2

b=-8, a=1, and c=8

Answer 3

I prefer:
\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \]
\.[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \]

Answer 4

that's more betterr

Answer 5

6.828, 1.17157

Answer 6

Car2021, You have everything you need to solve it, including some answers that you can use as a check.

Answer 7

ok so if i have \[8\pm 4\sqrt{2}/2\]..how would i solve that?

Answer 8

You could simplify further and get
\[4\pm 2\sqrt{2}\]

Answer 9

Solve for both roots

Answer 10

Use the + value for one root, then use the - for the other

\[4-2\sqrt{2}\]

Answer 11

\[4+2\sqrt{2}\]

Answer 12

soo would it be 2 sqrt 2 for one and 6 sqrt 2 for the other

Answer 13

Almost, first solve for the 2 times the square root of 2. this should give you a value of 2.828. Now with that you will use to get the two roots.
First add that to 4, that will be one root.
Then use it again subtracting it from four getting the second root.

Answer 14

Let me know what you get.

Answer 15

if, ax^2 + bx + c is a quadratic equation then we can find its roots by using a formula

http://upload.wikimedia.org/math/3/e/a/3ea647783b5121989cd87ca3bb558916.png

now try to solve it yourself. don't just go for the solution.

Answer 16

He has solved it down to the point of\[4\pm 2\sqrt{2}\]

Answer 17

radar ..when u get done will you help me?

Answer 18

or chatindia..lol

Answer 19

Yes, would be glad too, providing I can. I am just reviewing math from the past lol

Answer 20

lol okay thank you! :))

Answer 21

Is your problem already posted laurenlynn?

Answer 22

yes

Answer 23

it's the one that says PLEASE HELP ME!!! at the top..haha

Answer 24

O.K. I will look for it.

Answer 25

Car2021, I believe you have this problem whipped, cantorset has given you the actual answers in an early post of this thread. Good luck

Answer 26

what's the problem you are getting in solving this question. this latex code doesn't display in my phone. i can't understand this latex codes.