Question

At what value of X does the minimum or maximum occur for the function. F(x)= 2 (x+2)^2+8
A.) Minimum occurs at x=8
B.)Maximum occurs at X=-2
C.)Maximum occurs at x=8
D.) Minimum occurs at x=-2

Answer 1

For this, we need to calculate the derivative:
f(x)=2(x+2)² + 8
f'(x)=4x + 8

To determine where the minimum or maximum is, we solve f'(x)=0
4x+8=0
4x=-8
x=-2

Now, does f(x) have a maximum or a minimum?

Answer 2

maximum?

Answer 3

so its B

Answer 4

f(x)=2(x+2)² +8 = 2(x²+4x+4)+8=2x²+8x+16

Now, a=2, so f(x) has a minimum.

Look:
y=x² has a minimum, and a=1, which is positive.

Answer 5

So the answer is D

Answer 6

oh okay so it's minimum... duhhh and that would make it D

Answer 7

Thanks so much :)

Answer 8

That's my duty as mathematician.