Question

∫[0,1,(3x^(2)+2)^(2)x,]
Evaluate the definite integrals

Answer 1

\[\int\limits_{0}^{1}x(3x^2+2)^{2}dx\]

Answer 2

try to let u=3x^2+2
then du=6x dx or (du)/6=xdx
since x=1, then u=3(1)^2+2=5
since x=0, then u=3(0)^2+2=2
so we have \[\int\limits_{2}^{5}(1/6)*u^{2} du\]

Answer 3

So I don't need to do anything with the exponent on the outside the parenthesis which was actually sipposed to be a three not a two?