Question

Find f.
f ''(x) = 20x^3 + 12x^2 + 4
f(0) = 3
f(1) = 3
My Answer was x^5+x^4-2x+3
my answer was wrong, can someone tell me where I went wrong?

Answer 1

one sec

Answer 2

f'(x)=20x^4/4+12x^3/3+4x+C=5x^4+4x^3+4x+C
f(x)=5x^5/5+4x^4/4+4x^2/2+Cx+D=x^5+x^4+2x^2+Cx+D

Answer 3

what math are you in Calc I or II

Answer 4

1

Answer 5

okay I used integration, I'm assuming that you know how?

Answer 6

Yes

Answer 7

f(0)=D=3
f(1)=1+1+2+C+3=3 so C=-4

Answer 8

okay so take the integral of f double prime (c)

Answer 9

i mean (x)

Answer 10

so you get 20x^4/4 + 12x^3/3 + 4x

Answer 11

then simplify and do it once more

Answer 12

go it?

Answer 13

Medal pleaser ^.^

Answer 14

f(x)= x^5+x^4+C(x)+D

Answer 15

Plug f(0) in for x and set it equal to 3 makes D= 3
Plug f(1) in for x and set it equal to 3 makes C= -2
plugging those in was wrong

Answer 16

you are missing 2x^2 in f(x)

Answer 17

x^5 + x^4 + 2x^2 + c

Answer 18

myininaya solved it already

Answer 19

yeah

Answer 20

f(x)=x^5+x^4+2x^2+Cx+D

Answer 21

Thanks all