Question

how do you evaluate the integral of xe^(-x^2)dx on the integral (0,infinity)?

Answer 1

sub u=-x^2 so du=-2xdx

Answer 2

1/2\[Limit as R->\infty of 1/2 \int\limits_{0}^{R} \]

Answer 3

ah.. lol

Answer 4

I would do sub: u=x^2/2, so du=u and integral ( e^u du)... should be easy from this point

Answer 5

are you good with the improper integral part of it?

Answer 6

Let me know what your answer is

Answer 7

give me a min

Answer 8

Okay. Medal plz

Answer 9

Im getting:
integral (e^(-u)du)=-e(-u)
now: e^0=1
lim e(-u) when u is going to infinity = lim (1/ e^u) =0
my answer would be 1