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use implicit differentiation to solve: y^2-xy+x^2=2
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y'=(2-2x+y)/(2y-x) I did this fast so, you might want to check it.
you want to differentiate both sides
y is a function of x, so dy/dx will follow the chain rule
thus y^2 becomes 2y*y'
x^2 is explicitly expressed as a function of x, so there is no need to do chain rule for this one so x^2 just becomes 2x
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xy will follow the product rule because it is x times a function of x so it is like saying x*sin(x) you will do the product rule for xy and chain rule for y'
so it becomes y + xy'
all you do is to solve for y' from there :)
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