A certain population of bacteria contains 2380 individuals at noon on Monday and grows to 2430 after one hour.
Assuming the the growth is exponential, about how many will there be on noon that Wednesday?

Question

dumbcow · Answer

$$2430 = 2380e ^{k}$$
solve for k using ln
use that k value to find second part
t is in hours
$$P = 2380e ^{48k}$$

anonymous · Answer

what does k represent?

anonymous · Answer

and im supposed to solve with using ln or logs

dumbcow · Answer

$$P _{t}=P _{0}e ^{kt}$$
thats the general formula for exponential growth
k is a constant determined by initial conditions
yes because ln(e^k) = k

anonymous · Answer

but im not supposed to ln or logs

dumbcow · Answer

you have to solve this without using logs??

anonymous · Answer

yes

dumbcow · Answer

i dont know that you can, 
here are the answers then
k = 0.0208
P = 6456

anonymous · Answer

thanks