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OpenStudy (anonymous):
converge.
OpenStudy (anonymous):
why?
OpenStudy (anonymous):
I can't find a convergence test that is conclusive...Duke, what's your process?
OpenStudy (anonymous):
it's a geometric series.
OpenStudy (anonymous):
sequence*
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OpenStudy (anonymous):
I used comparison test. Assume 1/n -> diverges and (-1)^n/n converges. ( This is a fact.) Your sequence just has a 2+ which can be dropped since +/- are meaningless. You can also use the alter series test.
OpenStudy (anonymous):
*A alternating operator can turn sequence that normally diverge to converge.
OpenStudy (anonymous):
Actually, you don't just have a 2+...you have a 2/n (which is divergent). Check your parentheses.. normally I'd agree with you completely, but it breaks down into 2/n + (-1)^n/n.
OpenStudy (anonymous):
(2+((-1)^n))/n
OpenStudy (anonymous):
Exactly. That fraction degrades into 2/n + ((-1)^n)/n.
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