Work of 2 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (19 cm)? Don't forget to enter the correct units.

Question

anonymous · Answer

$$Work = Force\cdot distance$$
Work = 2 Joules
distance = .19 meters

anonymous · Answer

Work done , We = 1/2*kx^2
            2joules = 1/2*k*(0.19)^2
find k , spring constant

Force that holds the spring stretched = k*0.19 N