can anyone give me some examples of problems like " whats is the solution set for (x=1)^2=49?

Question

radar · Answer

Have you stated the example correctly?

anonymous · Answer

dang it. no...it was (x+1)^2=49

anonymous · Answer

(x+1)^2=7^2
so (x+1)=plus minus (7)
x=plus minus 6

radar · Answer

O.K  look like 6 would do it so would -8.  Lets work it out.

$$(x+1)^{2}= x ^{2}+2x+1=49$$
$$x ^{2}+2x-48=0$$
$$(x+8)(x-6)=0$$

anonymous · Answer

umm..the answer choices are in format of ( -48,48) and that kind of thing

radar · Answer

(x-6)=0, x=6
(x+8)=0, x=-8

radar · Answer

The solution set is x= 6, -8

radar · Answer

What exactly is asked for the example?

radar · Answer

Are you working on the "completing the square" method, or factoring or quadratic? for solutions??

anonymous · Answer

just solution sets. its part of the algebra 2 EOC, so i want to learn how to work them
 out

radar · Answer

method I used is called the "factoring method"  The quadratic equation was manipulated to equal 0 and then factored.

(x+8)(x-6) =0

The reason this works, one or both of the factors has to equal 0 for the results to equal 0.  Like, ab=0, then a or b or both equal 0.

anonymous · Answer

um...im actually not that good at math, just found this site..wish i had found it sooner though. i could have asked for help on my last project