How do I find the maximum profit....
0.8x^2+60x+120....

Question

amistre64 · Answer

do you know what the graph of this equation is going to resemble?

amistre64 · Answer

it looks like an upside down "U".... or rather, a frown.

amistre64 · Answer

the highest point of this graph tells you the max amount it can produce; and we call that point of this graph the vertex.

amistre64 · Answer

if you know calculus you can also get it by taking the derivative and setting it equal to zero; which gives you the vertex anyway :)

amistre64 · Answer

the x value of the vertex is given by the determinate of the quadratic formula:  -b/2a

in this case that amounts to:

-60/2(.8)

amistre64 · Answer

the max profit is then:

.8(-15/.4)^2 +60(-15/.4) + 120 = max profits

amistre64 · Answer

either i miscalculated or its a bad equation to begin with :)

 I get:  -1005

amistre64 · Answer

its a bad equation :) http://www.wolframalpha.com/input/?i=0.8x%5E2%2B60x%2B120

amistre64 · Answer

that should be a (-0.8x^2) if anything

amistre64 · Answer

otherwise the max profits are infinite :)

anonymous · Answer

there is no maximum. as stated the problem might be -x^2? Is there a domain given for X? If this problem is stated correctly it will be a boundary for X.