Question

i'm stuck on: integrate (cos(pi/x))/x^2

Answer 1

-(sin(pi/x)/pi)+ some constant (C)

Answer 2

i got the same answer.
assume (pi/x) = u
so du/dx = -pi/x^2
integral ((cos u)/x^2 ) . du x^2/-pi
(-1/pi) integral (cos u) du = (-1/pi) sin u
= (-1/pi) sin (pi/x)

Answer 3

thank you this helps!

Answer 4

you're welcome