how to solve using synthetic division....
(2x^5+2x^4+4x^3-2x^3-4x+3)/x+2

Question

amistre64 · Answer

2x^2 right?  thats a typo?

amistre64 · Answer

(x+2);   x = -2

-2|  2 +2 +4  -2    -4   +3
       0 -4 +4 -16 +36 -64
     ---------------------
       2 -2 +8 -18 +32 -61

anonymous · Answer

yea thats suppose to be 4x^3-2x^2

amistre64 · Answer

-61
2x^4 -2x^3 +8x^2 -18x +32  +  -----
                                                      (x+2)

anonymous · Answer

amistre64 =right!

amistre64 · Answer

yay!! .... i got one with out a typo lol

amistre64 · Answer

do you see how I got it mcoley?

anonymous · Answer

lol wait okay im lost which is the answer lol im trying to follow i confused myself

amistre64 · Answer

the first one is synthetic division to get all the "coefficiants" and a remainder:

(x+2);   x = -2

-2|  2 +2 +4  -2    -4   +3
       0 -4 +4 -16 +36 -64
     ---------------------
       2 -2 +8 -18 +32 -61


Next we apply these coeefecients and the remainder into their normal form of:

                                                      -61
2x^4 -2x^3 +8x^2 -18x +32  +  -----
                                                      (x+2)

It all depends on what format the "answer" is looking for really.

amistre64 · Answer

i should first ask if you understand how we did the synthetic division...  so do you?

anonymous · Answer

I see what your doing yea.. lol i get it

amistre64 · Answer

good:)

anonymous · Answer

I was trying to do it myself n i must have miscalculated

amistre64 · Answer

lol.... i miscalculate alot too :)