Question

Integral of 2^3xdx=

Answer 1

Make a guess: your u is usually the exponent or the bracket or under the radical or in the denominator or...

Answer 2

so for this one i'd use substitution?

Answer 3

you can substitute u=3x; du=3dx
this is standard table int...
answer: 1/3 * 2^(3x)/ln(2) +const

Answer 4

how'd you get ln(2)??

Answer 5

check the table of standard integral (in my #5):
int(a^u du)= a^u/(ln u) +c

Answer 6

if you would have e^x - int()= e^x, you have a base of 2 - this gives you ln2 in answer

Answer 7

break it to 2 integrals: int(2/cox thera) + int(cox^2(theta))/conx^2)= 2int(1/cox^2) + int(theta) d...
finish it - let me know if there is a problem

Answer 8

sorry,,, this is for another problem

Answer 9

ohh ok, I was confused for a sec lol