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OpenStudy (anonymous):
find the complx? 12+5i
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OpenStudy (amistre64):
find it?
OpenStudy (anonymous):
complex what? part? if complex part of the number - it's number in a front of i, so complex part=5
OpenStudy (amistre64):
real + imaginary maybe?
12 + 5i ; 5i is the imaginary part
OpenStudy (anonymous):
right!
OpenStudy (anonymous):
first we can find the modulus.
and the find . Arg angle .. by using tan inverse (y\x)
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OpenStudy (anonymous):
confused... what is the actual problem?
OpenStudy (amistre64):
teh modulus is the length of the line right? sqrt(144+25) = 13
OpenStudy (amistre64):
the angle is that of tan^-1(5/12) i spose
OpenStudy (amistre64):
if we plot this on reals; it would look like (12,5)
OpenStudy (anonymous):
its right. but agter we can use formula.
r(cos angle + i sin angle)
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OpenStudy (amistre64):
r(cos(t) + i sin(t)) is the polar coordinates...yes :) where r = 13 and t = that angle of tan^-1(5/12)
OpenStudy (amistre64):
t = 22.62 or so...
OpenStudy (anonymous):
is the ans 119
OpenStudy (anonymous):
how which formula to use?
to find
OpenStudy (anonymous):
do (12+5i)(12-5i)
144-25[i^{2}\]
169 is the ans
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