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when x^-1 is divided by x-1, find the quotient
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x^-1 is equivalent to 1/x, therefore you get the complex fraction of 1/x/(x-1)/1. When you have a complex (double-decker) fraction you can solve it by multiplying by top fraction by the reciprocal of the bottom one. Therefore; (1/x) * (x-1)/1, which is equal to (x-1)/x.
I don't get it. I see how x^-1 equals 1/x, but then I don't get how that becomes the double decker fraction.
the original problem was x^1 minus 1 (on top) divided by x-1. so where did the minus 1 go?
Please someone help!!
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