need help solving this inequality please. x -7

Question

need help solving this inequality please. x >-7

anonymous · Answer

...isn't that already solved?
You know the values of x. That's about as simple as it gets

anonymous · Answer

it's a question on an exam prep....

anonymous · Answer

hm... anything more to it than just "solve..."?

anonymous · Answer

So what are the values of x that satisfy the relation x > -7

anonymous · Answer

like choices? Otherwise i think im at a loss

myininaya · Answer

(-7,infinity)

anonymous · Answer

how would I graph it....thats the other part of the question...sorry guys

anonymous · Answer

$$x \in (-7, \infty)$$

Graph the relation? or the solutions?

anonymous · Answer

on a number line, draw it with an open circle on -7, with an arrow to the right

anonymous · Answer

Thanks Bwah!

anonymous · Answer

on a cartesian plane, a vertical line at x=-7, dotted (non inclusive). shade to the right

myininaya · Answer

x=-7 is a vertical line so since we have x>-7 and not x>=-7 then you draw a broken vertical line at x=7 and since we have x>-7 shade everything to the right 0f -7

anonymous · Answer

no prob, glad to help

anonymous · Answer

how about 3-10x>33

anonymous · Answer

well, the process is the same as any equation
u just have an inequality sign at the end

anonymous · Answer

Depends on which dimensions he has to include in the graph. In $R^1$ it's just a number line. In $R^2$ it is a field comprised of all (x,y) pairs such that $y\in (-\infty, \infty) \text{ and } x \in (-7, \infty)$ . In $R^3$ it would be a boxy thing, and so on.

anonymous · Answer

I think I am lost on the process :)

anonymous · Answer

How would you solve 3-10x = 33?

anonymous · Answer

-10x>30
x<-3 (if i recall correctly, u switch the sign if u divide or multiply by a negative number)

anonymous · Answer

subtract 3 from both sides?

anonymous · Answer

Indeed. You can do the same thing to inequalities.

anonymous · Answer

Then what would you do?

anonymous · Answer

divide by 10......I think I am seeing the light :)

anonymous · Answer

Yep. The only rule is that if you divide or multiply by a negative you have to change the direction of the inequality.

$-x < 5 \implies  x > 5$

anonymous · Answer

Ack

anonymous · Answer

$$-x < 5 \implies x > -5$$
rather

anonymous · Answer

Thanks so very much!

myininaya · Answer

I don't know if you have ever though of like if we have 5>2 then and we multiply both sides by negative one or divide by negative one then it becomes -5<-2 since -2 is bigger than -5

myininaya · Answer

any any negative number