Mathematics
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OpenStudy (anonymous):
Convert the rectangular coordinates to polar coordinates with r > 0 and 0 < θ < 2π.
(-9, 9)
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OpenStudy (anonymous):
You can use x= R cos t and y = R sin t
OpenStudy (amistre64):
r = 9sqrt(2)
OpenStudy (amistre64):
and its some form of 45 degree angle
OpenStudy (amistre64):
q2
OpenStudy (anonymous):
Find R by: R= sqrt(x^2 + y ^2)
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OpenStudy (amistre64):
angle = 135
OpenStudy (anonymous):
I know how to use the formula, but I can't use decimals as the answer.
OpenStudy (anonymous):
I have to put the answer in an x and y format.
OpenStudy (amistre64):
(9sqrt(2), 135) or the radian (3pi/4)
OpenStudy (anonymous):
how do u get this answer?
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OpenStudy (amistre64):
been going over spherical and cylindrical coordinates today lol
OpenStudy (amistre64):
well; i notice that both ax and y are the same; the only angle with that is a 45 degree; the hyp of a 45 degree is sqrt(2)
OpenStudy (amistre64):
r = 9 times bigger than sqrt(2) = 9sqrt(2)
OpenStudy (anonymous):
What about this one?
(-√21, -√7)
OpenStudy (anonymous):
oh ok
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OpenStudy (amistre64):
and the x=- and y=+ tells me its in the Q2
OpenStudy (amistre64):
r = sqrt(28)
the x=- and y=- is in the Q3
OpenStudy (anonymous):
sqrt28?
OpenStudy (amistre64):
tan^1(sqrt(7)/sqrt(21)) is the angle
OpenStudy (amistre64):
sqrt(21+7) = sqrt(28) right?
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OpenStudy (anonymous):
yeah, where to u get the 7 from?
OpenStudy (anonymous):
or why use the 7
OpenStudy (amistre64):
sqrt(7)^2 = 7
OpenStudy (amistre64):
7*4 = 28 so...2sqrt(7) = r
OpenStudy (amistre64):
tan^-1(sqrt(7)/sqrt(21)) + pi is the angle
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OpenStudy (amistre64):
we got 30 +pi :)
OpenStudy (anonymous):
so the y would be 7pi/6
OpenStudy (amistre64):
yes :)
OpenStudy (amistre64):
the angle = 7pi/6
OpenStudy (anonymous):
(-1, 0)
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OpenStudy (anonymous):
would it be (sqrt1,0)
OpenStudy (amistre64):
thats facing left....
r = 1; theta = pi
OpenStudy (anonymous):
why does theta = 0
OpenStudy (anonymous):
i mean pi
OpenStudy (amistre64):
it 1 from the origin; so r=1
and its 180 or pi from the pos x axis
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OpenStudy (amistre64):
theta doesnt equal 0, the y coord = 0
OpenStudy (anonymous):
the angle = pi
OpenStudy (amistre64):
if we turn by pi and move out by 1 we come to -1,0
OpenStudy (anonymous):
it's (1,pi)
OpenStudy (amistre64):
yes :) 1,pi
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OpenStudy (anonymous):
ok, a little change in direction.
OpenStudy (anonymous):
Convert the equation to polar form.
5x=5y
OpenStudy (amistre64):
thats the same as y = x which is
r = t cos(pi/4)
OpenStudy (amistre64):
or rather: (r,pi/4) i think
OpenStudy (amistre64):
could be +-r, pi/4
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OpenStudy (amistre64):
whats our options for answers?
OpenStudy (anonymous):
pi/4 is wrong, i tried thaat
OpenStudy (amistre64):
y=x is a 45 degree line.... cant be another angle :)
OpenStudy (amistre64):
x = r cos(pi/4)
y = r sin(pi/4)
OpenStudy (anonymous):
i'm so confused right now :(
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OpenStudy (amistre64):
maybe 5r, but thats rather redundant
OpenStudy (amistre64):
5x = 5y right?
5r cos(pi/4) = 5r sin(pi/4)
OpenStudy (amistre64):
the 5rs can be removed and you get; cos(pi/4)=sin(pi/4)
OpenStudy (anonymous):
is it 5r/sqrt2
OpenStudy (amistre64):
dont know; what formats you got to choose from?
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OpenStudy (anonymous):
i have no idea. what formats are there?
OpenStudy (amistre64):
if its multiple choice; then they give you options to choose from....any options to narrow this down with?
OpenStudy (anonymous):
no, no multiple choice.
OpenStudy (anonymous):
here's another example: x^2+y^2=16
OpenStudy (amistre64):
r^2 = 16
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OpenStudy (anonymous):
that would be 4. I tried that but it says it's wrong.
OpenStudy (amistre64):
then i got no idea what your program wants as an answer :)
OpenStudy (anonymous):
i got it i had to put it in as r=4
OpenStudy (anonymous):
y=2
OpenStudy (amistre64):
:)
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OpenStudy (anonymous):
would it be sqrt2
OpenStudy (amistre64):
y=2
r sin(t) = 2
OpenStudy (amistre64):
r = 2/sin(t) ?
OpenStudy (anonymous):
I don't get it.
OpenStudy (anonymous):
the question is Convert the equation to polar form.
y=2