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Find the volume of the solid obtained by rotating the region R bounded by the curves y = x and about the x-axis.
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y=x and ???
oops! y = x and y = 2sqrtx
something missing... y=x & what else? what is the boundaries? x=[0,?]
got it! give me sec
that better :) pi [S] x^2 - 4x dx from some interval lol
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x^3/3 - 2x^2
x=[0,4]
x = 2sqrt(x) x^2 = 4x x^2 - 4x = 0 x = 4/2 +- sqrt(16)/2 x = 2 +- 2; so o to 4
maaa!! iniks reading my mind again ;)
lol!
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64/3 - 32 is the answer
you are good with this one - I'll fish for something else. enjoy!
96 64 --- 32/3 = 10' 2/3
32/3 is the answer if i did it right ;)
Amistre HELP!!!
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where you at loco :)
the third question i just posted it
thanks amistre!
ur welcome :)
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