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Mathematics 7 Online
OpenStudy (anonymous):

graph all solutions to the following 2x+3y=6

OpenStudy (anonymous):

solve for y y = (6-2x)/3

OpenStudy (anonymous):

plug into graphing calc

OpenStudy (anonymous):

thanks but i dont have one

OpenStudy (anonymous):

try this: http://www.wolframalpha.com/

OpenStudy (anonymous):

i used matlab to plot this.

OpenStudy (anonymous):

plug the equation i gave u in there and then just copy it down

OpenStudy (anonymous):

Or you could just... you know... plug in two points and use a ruler?!?

OpenStudy (anonymous):

thank you I give it a try I am just having a hard time understanding how to plot or knowing when to when i look at a problem

OpenStudy (anonymous):

Ok, well pick an x that's nice (say 0). Then plug it in and find out what y is.

OpenStudy (anonymous):

what do you get for y?

OpenStudy (anonymous):

I did not know should I replace x with a 0?

OpenStudy (anonymous):

y = 3

OpenStudy (anonymous):

y= 0,3

OpenStudy (anonymous):

(x,y) = (0,3). Then do the same thing for y (plug in a 0) and find a second point

OpenStudy (anonymous):

for (x,y) = (?,0)

OpenStudy (anonymous):

Kool thank you so my answer is x=0,3 and y= 3,0?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

When you plug in a 0 for x you get y = 3 that's correct. That gives you the point (x,y) = (0,3). If you plug in a 0 for y you have this equation: \[0 = (6-2x)/3\]

OpenStudy (anonymous):

Which gives you \[x=3\] sorry, missread it. Ok, so now you have a second point (x,y) = (3,0)

OpenStudy (anonymous):

So you draw a Cartesian grid and draw those two points, then connect them with a straight line. That line represents all the x,y pairs that are solutions to the equation.

OpenStudy (anonymous):

You are so smart, that actually makes sense but what about y=5x-1 do i still use 0?

OpenStudy (anonymous):

would I go up 5 and down 1??

OpenStudy (anonymous):

If you are just being asked to graph it you can plug anything you want in for x or y (but not both!) then solve for the one you didn't plug in and you will have a point on the graph.

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