need help solve the system of equations by graphing then classify the system as consistent or inconsistent, and as dependent or independent 4x-y=15 x+5y=-12
inconsistent x=21/2 y=-9/2
would you plz show your work so i can figure out the next one on my own
by graphing, you can find the point of intersection as the solution.
will you plz show me how you got this
first you plot the graph of these linear equations. they are straight lines. 4x-y=15 is y=4x-15 which 15 is the y-intercept. to find the x-intercept, substitue y=0 into the equation. 0=4x-15 implies x=15/4. now u can draw the straight line. same goes on x+5y=-12. change it to y=mx+c then you'll get the y-intercept. to find x-intercept, substitute y=0. after that plot them and you'll get another straight line. after plotting, you can see there is a point of intersection which is the solution of this linear system.
i dont understand what the answer is what numbers do i plot
plot the x-intercept and y-intercept that you obtained and draw a line pass through the points :)
what are they? will you show your work
for 4x-y=15, you have x-intercept = 15/4 and y-intercept = 15. put a dot on x=15/4 on x-axis and put a dot on y=15 at y-axis.
then draw a straight line that pass through both of the dots. okay?
not sure how to plot 15/4
15/4 = 3 and 3/4. plot it in between 3 and 4 but close to 4 since the ratio is 3/4.
so it would be (0,3/4)?
15/4 is the x-intercept, you should draw it on x-axis. the coordinate is (15/4, 0). 15/4 is an improper fraction. you can change it into mixed number and you'll get 3+3/4 which is between 3 and 4 :)
ok so i put a dot on (0,15) and between 3 and 4 what about the 2nd equation of x+5y=-12
you're right. now we proceed to the next line. try to rearrange it into general form, y=mx+c.
5y=mx+-12?
5y=-x-12, divide all by 5, you'll get y=-x/5 -12/5. now you know the y-intercept is -12/5. try substituting y=0 and find the x value. that's how you obtain the x-intercept.
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