If f'(x)=sin[(pi*e^x)/2] abd f(0)=1, then f(2)=?? How do you do this when you can't take the integral of f'(x)
why cant you take the integral?
what level of precision is expected in the answer? because this could be approximated with a directional field.
vector fields eh..... ive seen them but havent played in them yet :)
its a practice problem on the calculus ab course description
it says not to inegrate?
Sorry, I meant slope field, is it multiple choice or open response?
slopes was my thought to; the slopes indicate the curve..... even outline it
it is multiple choice..
the choices are -1.819 -0.843 -0.819 0.157 1.157
well it doesn't say don't integrate... i just don't know how to integrate it
Then you should be able to construct f based on the slope f' at each x, and knowing that f(0) = 1, see how that process eliminates possibilities and gets you closer to selecting an answer.
oh....that makes sense...but u don't know any other values
That's okay, just start at f(0) = 1 and find f'(0) to know where the point next to x=0 would be and draw it on a graph. Continue this process until you see that some values are more likely than others. Maybe this process will be enough to get down to only one choice.
f'(x)=sin[(pi/2)*(e^x)] this is quite the same as sin(2*5^x)
hi amistre....are u a teacher or a student?lol
both :)
i thinks i got it...thanks
with the slopes?
slopes seem easier than the integral lol
i used a graphing calculator and graphed it from -1 to 4 to see the change in slope negative and positive to see if f(x) increases or decreases
amistre64, please show me how to integrate sin(2*5^x)
lol..been working on it :) seems a nightmare
integration is more of an art than a science ;)
never mind it didn't work...the first derivative doesn't help
there aint no sin(ab) identities are there...
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