Question

the sum of the digits of two-digit number is 15. if the digist are reversed the new number is 27 less than the original number. Find the original number

Answer 1

interesting problem

Answer 2

let's say that the 10th digit is a and the units to be b

Answer 3

then a + b = 15

Answer 4

our two digit number can be represented as 10a + b

Answer 5

so if you reverse the order it becomes 10b + a

Answer 6

the new one is 27 less than the original number, so your
other equation will be

10b+a = 10a+b -27

Answer 7

now that you have two equations with two unknowns,
you can solve for the system of equations.

Answer 8

please help me with the answer :(

Answer 9

the two eqs are
a+b=10
10b+a-10a-b=-27
9a-9b=-27

Answer 10

which is it a+b=15 or a+b=10?

Answer 11

ah...a+b=15

Answer 12

Did you guys find the number?

Answer 13

a+b=15
9a-9b=-27 are the two eqs
solving the two eqs...
a=6 n b=9

Answer 14

96 , 9+6=15
69=96-27

Answer 15

So, the original number is 96.

Answer 16

Looks like a good Bingo lol

Answer 17

but as yuki took the places of digits,,10a+b gives 69:S

Answer 18

i guess second eq should be
10b+a+27=10a+b
???

Answer 19

I gave yuki a medal anyway

Answer 20

You're getting one too

Answer 21

:)

Answer 22

n u know i made mistake in solving a qs too :P

Answer 23

It is the spirit of the effort that counts.

Answer 24

right...but it surly confuses the one who posts the question

Answer 25

thank you guys u are life saaaavvveeeerrrssss