Question

can any one solve this?(log(a)(x^3))+(log(a)(sqrtx))=
answer has to be in klog(a)x form
thanks already :)

Answer 1

is that base a?

Answer 2

log[a](x^3) like this?

Answer 3

3loga(x) + (1/2)loga(x)

Answer 4

loga(x)(3+(1/2)) ??

Answer 5

Amistre, I think contact has been lost lol.

Answer 6

looks right lol

(6/2) loga (x)

Answer 7

:) but the math remains lol

Answer 8

Hahahaa, so very true!

Answer 9

(7/2) loga(x)

Answer 10

yes a is the base, soz my internet played up :S

Answer 11

can we factor out the loga(x) like that tho?

Answer 12

\[\log_{a} x^3+\log_{a} sqrtx\]

Answer 13

if we multiply it togeter again we get:

loga[sqrt(x^7)] so its good

Answer 14

(7/2) loga(x) is your answer

Answer 15

where did 7 come from?
soz but i dont get the stuff you lot did at the top :S

Answer 16

3 + 1/2 = 3' 1/2 to get it into an improper fraction (topheavy) we multiply 3 by the denom and add the numerator;

3(2) = 6 + 1 = 7.... 7/2

Answer 17

OR we could go the route of changing addition of logs back into multiplication of logs

Answer 18

ok :)
multiplication logs?

Answer 19

loga(x^3 sqrt(x)) = loga(sqrt(x^7)) = loga(x^(7/2))

(7/2) loga(x)

Answer 20

loga(x) + loga(y) = loga(xy)

Answer 21

loga(x^n) = n loga(x) as well

Answer 22

ok
so 7/2logax is the answer right?

Answer 23

yes; (7/2) loga(x) is the answer

Answer 24

\[7/2\log_{a} x\]

Answer 25

yay!
ill give u all medals :)
thx

Answer 26

im gonna need a new cigar box to keep these things in ;)

Answer 27

:p