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OpenStudy (anonymous):

Could someone please answer this question The gradient of a curve is (6x^2)+(12x^1/2). The curve passes through the point (4,10). Find the equation of the curve. thanks :)

OpenStudy (anonymous):

gradient is slope ?

OpenStudy (anonymous):

im not sure but i think it is because whenever i mention gradient people go on about slopes :p

OpenStudy (anonymous):

hello miss, i couldn't understand the question. can you write it in the same way as in your assignment

OpenStudy (anonymous):

\[6x ^{2}+12\sqrt{x}\]

OpenStudy (anonymous):

q6) The gradient of a curve is (6x^2)+(12x^1/2). The curve passes through the point (4,10). Find the equation of the curve. (5marks)

OpenStudy (anonymous):

\[6x^2+12x^0.5\]

OpenStudy (anonymous):

in which standard you are miss???

OpenStudy (anonymous):

what do you mean? what standard?

OpenStudy (anonymous):

which class??

OpenStudy (anonymous):

AS=Alevel why?!

OpenStudy (anonymous):

just to know how deep i have to go answering this question

OpenStudy (anonymous):

oh, so you know how to do it :) yay!

OpenStudy (anonymous):

i know how to do such question but something is odd in this question

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

nothing!! okay, tell me what you mean by slope of a curve???

OpenStudy (anonymous):

the gradient

OpenStudy (anonymous):

and that that gradient passes through that equation and i need to use the points to make and equation this is what i assume

OpenStudy (anonymous):

i think from the gradient/slope a curve, one mean the slope of the tangent line at any point of the curve

OpenStudy (anonymous):

but the points are 4,10

OpenStudy (anonymous):

hmm, how you find the slope of the curve???

OpenStudy (anonymous):

are you getting the hint????

OpenStudy (anonymous):

i think you now know, how to solve this question. if you still face problem then post it here and i'll solve it for you.

OpenStudy (anonymous):

what hint? i still dont get it

OpenStudy (anonymous):

okay, tell me how you find the slope of the curve

OpenStudy (anonymous):

y2-y1/x2-x1

OpenStudy (anonymous):

that's the way to find the slope of a straight line :P

OpenStudy (anonymous):

i asked for curve (in general)

OpenStudy (anonymous):

huh? soz dunno what ur talkin about the equation?

OpenStudy (anonymous):

do you know differentiation and integration???

OpenStudy (anonymous):

not sure :S i get confused with them both

OpenStudy (anonymous):

wait, differentiation finds the gradient, doesnt it

OpenStudy (anonymous):

if differentiation of the curve equation finds the gradient (as you said) then will the integration of the gradient equation gives the curve equation???

OpenStudy (anonymous):

this is really confusing :(

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