solve by using the substitution method
x+y=6
x+4y=3

Question

solve by using the substitution method 
x+y=6
x+4y=3

anonymous · Answer

From the first equation, x=6-y. Substitute this value of x into the 2nd equation, you get:
$$6-y+4y=3 \implies 6+3y=3 \implies 3y=-3 \implies y=-1$$
So, we have y=-1.
Now, substitute this value of y in equation (1) to  get x:
$$x-1=6 \implies x=7$$
That's the solution of the system is is x=7 and y=-1

anonymous · Answer

can you help me to sove some more ??please 
solve by the addition method
2x+y=11
x-y=11

anonymous · Answer

Ok, Can you add equation (1) to equation (2)?

anonymous · Answer

is 4+3 -6?

anonymous · Answer

You should add the x's together, the y's together and the constants together. That would give you:
3x=22  ---> x=22/3
Substitute this value of x in equation (2) to find y.

anonymous · Answer

and i also need help to solve this one the last one 
3x-2y=12
5x+2y=4