Question

solve by using the substitution method
x+y=6
x+4y=3

Answer 1

From the first equation, x=6-y. Substitute this value of x into the 2nd equation, you get:
\[6-y+4y=3 \implies 6+3y=3 \implies 3y=-3 \implies y=-1\]
So, we have y=-1.
Now, substitute this value of y in equation (1) to get x:
\[x-1=6 \implies x=7\]
That's the solution of the system is is x=7 and y=-1

Answer 2

can you help me to sove some more ??please
solve by the addition method
2x+y=11
x-y=11

Answer 3

Ok, Can you add equation (1) to equation (2)?

Answer 4

is 4+3 -6?

Answer 5

You should add the x's together, the y's together and the constants together. That would give you:
3x=22 ---> x=22/3
Substitute this value of x in equation (2) to find y.

Answer 6

and i also need help to solve this one the last one
3x-2y=12
5x+2y=4