Question

What is the y intercept of x/7-4y=-2

Answer 1

rearrange the equation into general form of straight line, y=mx+c which c is the y-intercept.

Answer 2

How do you write this in standard form?

Answer 3

x/7-4y=-2,
-4y=-2- x/7,
y=1/2 + x/28.

Answer 4

I would put it in standard form by first multiplying both sides of the equation by 7 to get rid of the denominator in the first term: x/7
That would be
\[(\frac{x}{7}-4y)*7 = -2*7\]
then distributing on the left you get
\[\frac{x}{7}*7-4y*7 = -2*7\]
which is
\[\frac{x}{7}*\frac{7}{1}-4y*7 = -2*7\]
and the first term reduces to x since the 7's cancel
so you get
\[x-28y=-14\]
Now isolate y on one side of the equation by putting all the terms without y on the other and dividing each term by -28

Answer 5

\[x-28y=-14 \]
-x -x
\[\frac{-28y}{-28}=\frac{-x}{-28}-\frac{14}{-28}\]
\[\frac{-28y}{-28}=\frac{-x}{-28}+\frac{-14}{-28}\]
which simplifies to
\[y=\frac{x}{28}+\frac{1}{2}\]

c is \[\frac{1}{2}\]

Does that help? :)