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the derivative for y=(x+1)(x-3)^3
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3(x+1)(x-3)^2
no, you have to do product rule. you get 3(x+1)(x-3)^2 + (x-3)^3 hope that helps
i'm suppose to get 4x(x-3)^2??
yeah, so take my answer and factor out (x-3)^2. that leaves you 3(x+1) + (x-3) in the parentheses, which is 3x+3+x-3 = 4x. let me know if that doesn't make sense. :)
wait what happen to the (x-3)^3 that later turned into (x-3)
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what i did was factor out (x-3)^2 from that. both of your terms have (x-3)^2 as a common factor.
ok got it:)
good to hear, nice job.
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