Question

differentiate 2sin^2x + sin2x^2

Answer 1

correction: sin^2(2x) + sin2x^2

Answer 2

so you're saying
\[\sin^2(2x)+\sin(2*x^2)\]
or is it
\[\sin^2(2x)+\sin((2x)^2)\]
?

Answer 3

the first one

Answer 4

ok then you can also write it like:
\[(\sin(2x))^2+\sin(2x^2)\]
and use the chain rule for differentiation in both terms:
The derivative of the first term is
\[2(\sin(2x))^1*\cos(2x)*2\]
The derivative of the second term is
\[\cos(2x^2)*4x\]
The answer is the two of these derivatives added together.

Does that help?

Answer 5

thanks alot..

Answer 6

:)