Question

I have to prove that tan(alpha)=sen(alpha)/Cos(alpha) for the following figure ...

Answer 1

Im not sure is what I did is righ. Please check it out for me:

Tan(alpha)=TU/OU (1)

if
sin(alpha)=TU/OT, then TU=OTSen(alpha) (2)
cos(alpha)=OU/OT, then OU=OTCos(alpha) (3)

replacing TU and OU in equation 1, I got

Tan(alpha)=Sen(alpha)/Cos(alpha)

Is that correct?

Answer 2

with sen do you mean sin?
and the thing you wrote is a trigonomerty identy

Answer 3

yeah sorry Sen=Sin

Answer 4

yea, so
tan(theta)=sin(theta)/cos (theta)

wehen i say (theta) that is just an unknown number
could be x or anything :)

Answer 5

thats an identiy so what are you trying to work out?

Answer 6

in the graph I attached you can se that the angle is alpha. However, we can call it theta. The point of this all is to prove the above statement

Answer 7

sorry, id love to help but i dont understand your graph :S

Answer 8

It ok my friend :)
by the way. Can you help me with analithic geometry? how to determine the center of a circumference?

Answer 9

sorry for the typos, but my native language is spanish, no english

Answer 10

i can give it a try but i can garantee that ur gonna get and answer :S