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integrate: (1+lnx)e^(xlnx) dx
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\[\int\limits_{}^{}(1+\ln x)e^{x lnx}\]
e^(xlnx) +C
[S] Du e^u du -> e^u
D(x ln(x)) = 1+ln(x) :)
can u explain the steps?
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integration is not s step procedure; it is an art form. The best thing to do is to realize that (1+ln(x)) is the derivative of x ln(x). We should know by now that the derivative of e^u = Du e^u so to suit it back up we just revert it to e^u again..... You have the structure Du e^u... so the answer is simply e^u; with u=xlnx
thanx.. i really appreciate it
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