Question

find the x value of the point of the curve y=3x+2 closest to the point (1,0)

Answer 1

That equation is not a curved line, that equation is a straight line (y=mx+b),

Answer 2

ok...but this is what it says on my test

Answer 3

What class?

Answer 4

calculus I

Answer 5

distance=d=sqrt((1-x)^2+(0-(3x+2)^2)
minimizing distance will give you same minimum if you minimize d^2
d^2=(1-x)^2+(3x+2)^2
(d^2)'=..... you finish this i have to go

Answer 6

you could find the min value between the point (1,0) and (x,3x+2) using the distance formula and then set the derivative of the distance fomula to 0

Answer 7

oh ok. Thnks guys