Question

Ten cards are numbered from 1 to 10 and placed in a box. One card is selected at random and replaced. Another card is selected at random. What is The probability of selecting a multiple of 3 and then a multiple of 2?

Answer 1

How many multiples of 3 are there, and how many multiples of 2?

Answer 2

the probability of selecting multiples of 3 and multiples of 2

Answer 3

I'm confused.

Answer 4

No, I'm saying count how many there are first.

1
2 is a multiple of 2
3 is a multiple of 3
4 is a multiple of 2
5
6 is a multiple of 2 and a multiple of 3
7
8 is a multiple of 2
9 is a multiple of 3
10

So how many multiples of 2 are there in the box?
How many multiples of 3?

Answer 5

4 multiples of 2 and 3 multiples of 3.

Answer 6

Count again.

Answer 7

5 multiples of 2 and 3 multiples of 3

Answer 8

Correct.

So when you pick the first card, what is the probability it will be a multiple of 3?

Answer 9

3

Answer 10

30%

Answer 11

Ok, and you put the first card back and pick again. What are the odds of picking a multiple of 2?

Answer 12

50%

Answer 13

Correct.

So the odds of doing one and the other is:

P(A and B) = P(A) * P(B) = .3 * .5 =

Answer 14

So 15%

Answer 15

I believe that should be correct yes.