how can i solve a quadratic equation like this 6x^2-5+x=0
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OpenStudy (anonymous):
rewrite it in the normal form and plug into the quadratic equation:
\[ax^2 + bx + c = 0 \implies x = \frac{-(b) \pm \sqrt{(b)^2-4(a)(c)}}{2(a)}\]
OpenStudy (anonymous):
thank you i did that part but where i am getting cofused at is that addition/ subtraction sign i dont kno what to do with it sorry i didnt say that earlier
OpenStudy (anonymous):
Oh, well unless the part under the square root is 0 you will get 2 different possible solutions.
\[x = \frac{-(b) + \sqrt{(b)^2-4(a)(c)}}{2(a)}\]
and
\[x = \frac{-(b) - \sqrt{(b)^2-4(a)(c)}}{2(a)}\]
The \(\pm\) thing just makes it easier to write.
OpenStudy (anonymous):
oh ok thank you i'ma try it now :D
OpenStudy (anonymous):
HOW WOUD I GET THAT SQUARE ROOT SYMBOL ON THE CALCULATOR
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OpenStudy (anonymous):
It should have it. If not you can raise it to the .5 power.
OpenStudy (anonymous):
LIKE THIS (1^2-4(6)(-5)^5
OpenStudy (anonymous):
it gave me some crazy number how would you do it i guess i was wrong
OpenStudy (anonymous):
i got 2.59374246E10
OpenStudy (anonymous):
Not quite. What do you have before you plug it in?
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OpenStudy (anonymous):
i did 1^2-4(6)(-5) and i recieved 121 but then i raised that to the 5th power and i got that wierd number
OpenStudy (anonymous):
but then instead of that i subtracted -5 then i divided by 12 and i got 10.5
OpenStudy (anonymous):
?
OpenStudy (anonymous):
why did you raise to the 5th. I said .5 or 0.5 or 1/2
OpenStudy (anonymous):
that's probably the issue.
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OpenStudy (anonymous):
i still dnt get it i'm sorry for wasting your time!
OpenStudy (anonymous):
Your calculator doesn't have a square root button?
OpenStudy (anonymous):
it does but it is a blue sign above the X^2 button i cnt seem to get the sign but i always get the X^2
OpenStudy (anonymous):
?
OpenStudy (anonymous):
What kind of calculator do you have
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OpenStudy (anonymous):
a TI-84 PLUS SILVER ADDITION
OpenStudy (anonymous):
Do you see the blue func button? Press that first, then press the x^2 button.
OpenStudy (anonymous):
err should say 2nd on it.
OpenStudy (anonymous):
I GOT IT! yah thanx yu
OpenStudy (anonymous):
i got a -48
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OpenStudy (anonymous):
The square root of 121 is 11
OpenStudy (anonymous):
So you should have
\[x = \frac{-1 \pm 11}{2(6)}\]
OpenStudy (anonymous):
i feel so dum sorry!
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
hrm?
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OpenStudy (anonymous):
i got 32and -34 do i put down both of my answers
OpenStudy (anonymous):
How do you get that?
OpenStudy (anonymous):
-1 + 11 = 10
-1 - 11 = -12
So you should have 10/12 and -12/12 = -1
OpenStudy (anonymous):
omg! im sorry but im dne i cnt do this!
OpenStudy (anonymous):
I don't understand what's confusing you.
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OpenStudy (anonymous):
If you can explain I can try to help.
OpenStudy (anonymous):
i just dont know how to do this im basically confused about evrything i dnt know what else to do
OpenStudy (anonymous):
Well hang on.
OpenStudy (anonymous):
Can you simplify the expression
\[\frac{4+3}{8}\]
OpenStudy (anonymous):
7/8
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OpenStudy (anonymous):
1.142857143?
OpenStudy (anonymous):
no im sorry 7/8
OpenStudy (anonymous):
u k i have no idea wat ur sayin im in 5th grade
'
OpenStudy (anonymous):
?
OpenStudy (anonymous):
Yes, 7/8 is correct
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OpenStudy (anonymous):
Now try this one:
\[\frac{4-3}{2(4)}\]
OpenStudy (anonymous):
polpok ur awesome
OpenStudy (anonymous):
heh, thanks.
OpenStudy (anonymous):
np
OpenStudy (anonymous):
When working with fractions like this, just try to simplify the top and bottom separately.