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Mathematics 15 Online
OpenStudy (anonymous):

Find the volume of the solid formed by rotating the region bounded by: y=x^2+2 and y=x+8 around the line, x=4. Leave the answer in terms of pi.

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

lolz

OpenStudy (yuki):

so what you are basically doing is to find the volume of the washer (I usually call it a ring) and integrate it. what do you think the integrand is ?

OpenStudy (yuki):

OpenStudy (yuki):

if you see that the volume of each ring(washer) has a volume V = 2pi ( (4-sqrt(y-2))^2 - (4-(y-8))^2) dx so the integration will be\[2\pi \int\limits (4-\sqrt(y-2))^2- (4-(y-8))^2dx\]

OpenStudy (yuki):

oops, I meant dy

OpenStudy (yuki):

now all you have to do is to figure out the limit of integration

OpenStudy (yuki):

the bottom of the parabola starts at y = 2 and it ends at y = 11 so the limit of integration is from 2 to 11

OpenStudy (yuki):

once you integrate it you are done :)

OpenStudy (yuki):

If you would like, try using the shell method, which is also a good choice for this one :)

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