solve 3/x-2+1=-23+7x/(x-2)(x-3)
are there any parenthesis in the first part or is it just x-2+1?
yea that IS a bit confusing.... :P
the way you write the question makes it a bit hard to understand
wat u talkin about
u need to space it out a bit that would make it easier to solve for both us and urself :)
3 / x-2 +1 = -23+7 / (x-2) (x-3)
ok
im waiting on u to solve it
Does it look like \[3/(x-2)+1=-23+7x/(x-2)(x-3)\] ?
\[(3+x-2)(x-3)=-23(x-3)+7x\] \[(1+x)(x-3)=-23x+69+7x\]
Now you can do the rest, can't you coreeta?
can u solve x for me
Well, that would be as follows \[x-3+x^2-3x=-16x+69\]
\[x^2+14x-72=0\] If I am not mistaken anywhere through out the solution
Do you know how to solve quadratics equation?
\[{{x = (31 -Sqrt[151])/12}, {x = (31 + Sqrt[151])/12}} \]
what is the values of x in this problem
I think I have done it wrong somewhere. I mean some silly mistake It must be \[3/x+7/(x-2)+15 = 0\]
\[3/x = (23-15 x)/(x-2)\]
Now you got to cross multiply, and then solve the quadratic equation
i dont no know to do that im homeskooled
Which level you are currently in?
im n 9th . can u plz find the valuse of x for me
Do you just need the answers or you need to understand the steps?
i need the answer
Okay, then forget everything I did there. I did several mistakes. Actually its quite tough to type things here
I am doing it on a piece of paper, and telling you the answer
ok
pi when you finish tell me if ur answer look anything like this x=-0.252 and x=1.585
First coreeta, have a look at this, Does your equation looks like the one I have attached
If so then your solutions are
yes that is right
and the another solution for x is
These are the final answers and they are correct, (I am 100% sure)
The solutions are \[x = 1/12 (31-\sqrt(151))\] \[x = 1/12 (31+\sqrt(151))\]
Is it okay coreeta?
yes
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