Question

Find an equation of a line parallel to the line 3x-2y=4 and containing the point (3,-5)

Answer 1

\[2y=4\]is this wat u tryin to find

Answer 2

yes

Answer 3

parallel = means the same slope
re-write your ew as:
2y=3x-4 or y=3/2 x -2
so, slope your existing line is: m=3/2
so, eq of parallel through the point (3,5):
y-5=3/2 *(x-3)
y=3/2x -9/2 +5=3/2 x+1/2

Answer 4

That makes sense.... Thank you!

Answer 5

Can you help me with another one?

Answer 6

shoot... I need to go soon

Answer 7

Its like the one you just helped me with only perpendicular to the line 3x-2y=4 and containing points 3,-5

Answer 8

try to do it yourself - I'll help.
just remember that perpendicular means that your line will have slope (m2) = -1/m1...
so, if re-write your eq:
y=3/2 x -2
so, for perp line: m2=-2/3
eq of the line:
y-(-5)=-2/3 (x-3)
simplify, please

Answer 9

So then y=-2/3x+6/3-5?

Answer 10

y+5=-2/3 *x +2
y=-2/3 *x -3

Answer 11

do you see it?

Answer 12

So the equation is y=-2/3x-3?

Answer 13

yep... to be exact:
y=(-2x/3 ) -3

Answer 14

Okay, I guess I just don't get how you suddenly got to x+2 in the end

Answer 15

let's go back to:
y-(-5)=-2/3 (x-3)
i think that the way it written it could be confusing... let's try differently:
y+5= x* (-2/3) -3* (-2/3)
y+5=-2x/3 +2 (-3 in numerator & -3 in dominator are canceled out)

is it better...?

Answer 16

That does make better sense. Math is like a whole other language for me, lol. Thank you so much for your help

Answer 17

Great! Welcome :)