A ball was thrown at 50miles per second and it was to reach 3000miles what is the angle that it needs to be thrown to hit the destination? with the formula r=(1/32)(Vo)^2sin2

Question

anonymous · Answer

hi nikko maybe theres a letter x or y next to sin2,,,like 2sin2x? so that you can solve for the double angle x.....?
is it maybe like this: r=(1/32)(Vo)^2sin2x.....
now you can use the logarithm process....

anonymous · Answer

32r=(Vo)^2sin2x
log(32r)=(2sin2x) log(Vo)
sin2x=(log32r)/(2log(Vo))
2x=arc sin((log32r)/2logVo)...now you can plug in the given datas into this formula
2x=arc sin(log(32*3000)/2log50)
2x=arc sin(4.9822/3.3974)
2x=arc sin(1.466)  hmmmmm sin 1.466 is not right..its not suppose to be greater than 1

anonymous · Answer

seems like something are missing in the prpblem