can anyone help me with solving problems with Exponential and Logarithmic
whats the prob be?
holly wants to save money for an emergency. holly invests $1200 in an account that pays an interest rate of 4%. how many years will it take for the account to reach $15,400? round your answer to the nearest hundredth
15400=1200(1.04)^t
154 ---- = 1.04^t 12
t = log1.04(154/12)
140.714 is what i got. correct?
we can do change of base to be able to do this on a calculator...
log(154/12) ---------- log(1.04)
65.07 years?
you can always double check by plugging your answer into the original...
15400 ?=? 1200(1.04)^(65.07)
15400.706
so 65.07 is correct?
i believe it is..... but i dont know how your program accepts its answers.... it may be off by 1/100
it was right!
yay!!
You invest $4,900 in an account that pays an interest rate of 5.5%, compounded continuously. Calculate the balance of your account after 6 years. Round your answer to the nearest hundredth,
cant get medals if no new questions are posted lol.....
pert again....
4900(e^(.055)(6))
plug that into google and the calc will spit back an answer
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