Mathematics
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OpenStudy (anonymous):
find xy+(z^3)x-2yz=0 in terms of z
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OpenStudy (anonymous):
whts in terms of z mean?
OpenStudy (anonymous):
the answer should be z= f(x,y). so i am asking what f(x,y) is
OpenStudy (amistre64):
x.z^3 -2yz = -xy
OpenStudy (amistre64):
z(-2y +x.z^2) = -xy
-2y +x.z^2 - -xy/z
OpenStudy (anonymous):
It's complicated to solve for z.
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OpenStudy (anonymous):
yeah its a cubic eqn in z
OpenStudy (anonymous):
Could you write the original question, if it is not this?
OpenStudy (amistre64):
-2y +x.z^2 = -xy/z
x.z^2 = (-xy+2yz)/z
z^3 = (-xy+2yz)/x
OpenStudy (anonymous):
i am supposed to find dz/dx at the point (1,1,1) of that equation
OpenStudy (anonymous):
then say that
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OpenStudy (anonymous):
spo i assumed i needed z as a function of x and y
OpenStudy (amistre64):
you dont need to solve for z then...
OpenStudy (anonymous):
u dont need to..i think not
OpenStudy (amistre64):
dz/dx = g(F).d(xbar)/dx
OpenStudy (anonymous):
ok, sorry about tha
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OpenStudy (anonymous):
You don't have to solve for z.
OpenStudy (anonymous):
bt then how to do it???
OpenStudy (amistre64):
get the gradient vector but partialling the equation of the plane there
OpenStudy (amistre64):
get the gradient vector but partialling the equation of the plane there
OpenStudy (amistre64):
F=<a,b,c>
a = dz/dx...but not that dz/dx...the funny looking one lol
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OpenStudy (anonymous):
then do df/dx / df/dz?
OpenStudy (amistre64):
<y+z^3, x-2z, 3z^2-2y>
OpenStudy (amistre64):
plug in the values from your point know to get the gradianet vector
OpenStudy (amistre64):
<2,-1,1> is your normal vector/gradient..
OpenStudy (anonymous):
oh ok, i got the gradient vector, then plug in the point (1,1,1) to df/dx to get the answer?
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OpenStudy (amistre64):
dot product that with the vecotr that is the point...<1,1,1>
OpenStudy (anonymous):
i got <2, -1, 1> yes
OpenStudy (amistre64):
2(x-1)-1(y-1)+1(z-1) = dz/dx i think :)
OpenStudy (anonymous):
is it right??
OpenStudy (anonymous):
is that the plane equation?
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OpenStudy (anonymous):
i dont have the answer
OpenStudy (amistre64):
that is the plane equation
OpenStudy (anonymous):
doesnt the gradient vector give <df/dx, df/dy,df/dz>... in that case we can simply do df/dx / df/dz???
OpenStudy (anonymous):
the answer isnt an equation...its a value
OpenStudy (amistre64):
him; dunno havent read that far yet :)
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OpenStudy (anonymous):
thats wht m sayin
OpenStudy (anonymous):
is the answer 2???
OpenStudy (amistre64):
the answer would be 2 then right?
OpenStudy (amistre64):
gradient . point
OpenStudy (anonymous):
i think so! thanks!
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OpenStudy (anonymous):
is it 2??
OpenStudy (anonymous):
i dont know the value, but it seems right
OpenStudy (anonymous):
u understood how it ws done?
OpenStudy (amistre64):
i dont think I evenknow how it was done lol
OpenStudy (anonymous):
I got -2.
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OpenStudy (anonymous):
yes, get the gradient, and plug in the x,y and z valuse of the point into the gradient and divide df/dx by df/dz to get dz/dx right?
OpenStudy (anonymous):
Not entirely sure though.
OpenStudy (anonymous):
i thnk it shld be right..there might b calculation errors bt b surev f d method
OpenStudy (amistre64):
<2,-1,1>
<1, 1,1>
---------
2 -1 +1 = 2
OpenStudy (anonymous):
so i said
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OpenStudy (anonymous):
david wht grade u in?
OpenStudy (anonymous):
im a sophomore in college. im studying for my calc 3 final