How do you get this?:)
let f(x)=(x+2)/(x+8)
f^-1(-9)=?
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OpenStudy (amistre64):
you want the inverse of f(x)
OpenStudy (anonymous):
\[f^(-1)(x) = -(2 (4 x-1))/(x-1)\]
OpenStudy (amistre64):
the inverse is gotten suslly by switching x and y and resolves for y
OpenStudy (anonymous):
You don't have to find the inverse, Just plug f(x)=-9, and then solve for x. That value of x is the inverse at x=-9.
OpenStudy (anonymous):
let y = x+2 / x+8
yx + 8y = x+2
x(1-y) = 8y-2
x = (8y-2)/1-y
which gives u d inverse
now switch x and y
and put in d value of x to get y
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OpenStudy (anonymous):
thank you!:)
OpenStudy (amistre64):
x=(y+2)/(y+8)
x(y+8)=y+2
xy +8x = y+2
xy - y = -8x +2
y(x-1) = -8x+2
y = (-8x+2)
-------
(x-1)
OpenStudy (amistre64):
y = (-8(-9)+2)/(-9-1)
y = 74/-10 = -7.4
OpenStudy (anonymous):
welll i did the very same
OpenStudy (amistre64):
yay!! its verified then ;)
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OpenStudy (anonymous):
A simpler method, is to plug f(x)=-9 and then solve for x:
\[-9={x+2 \over x+8} \implies -9x-72=x+2 \implies 10x=-74 \implies x=- 7.4\]
So,\[f^{-1}(-9)=-7.4\]