What is the equation of the tangent plane to the function: 2x^2 +y^2 +2z^2 +2xz =7. At the point (-1,1,2) ?
it begins with the gradient....
yeah thatl giv u d direction ratios of the tangent plane
4x+2z, 2y, 4z+2x thats 0, 2, 6
goody goody goody :)
but then how do u get the direction ratios of the normal?
the normal is <0,2,6>; so use the point to calibrate the equation
thats the ratios parallel to the plane
0(x+1)+2(y-1)+6(z-2)=0
thats wrong
those coefficients have to be in the direction of the normal, and not the tangent
can you explain?
n=<a,b,c>; P=(x0,y0,z0) equation of the plane: a(x-x0)+b(y-y0)+c(z-z0)=0 is the way the textbook tells me it
ur using the standard eqn of a plane passing through a given pt a,b,c A(x-a) + B(x-b) +C(x-c)=0 where A,B,C are direction ratios of the NORMAL
x-x0; y-y0 and z-z0 are the components of the vector on the plane
u get the cross product of <0,2,6> and <-1, 1,2>
thatl give u a vector normal to the plane say <A,B,C>
then use the standard equation
-1,1,2 is a point on the plane right? not a vector parallel to it tho.
yeah
the vector that is parallel to the plane is (x-x0,y-y0,z-z0) where P(x0,y0,z0) is on the plane right?
-2(x+1) +6(y-1) +2 (z-2) = 0
-2,6,2 is not the normal to the tangent plane tho. if anything it too is parallel to the plane
arent you suppose to find Fx(X,Y) and Fy(X,Y) use the cross product to find the N?
i told u get the vector product of the direction of the tangent and the point
weve already found the gradient, i suggest we cross that with the point to get a vector normal to the plane
the normal was found by the gradient; isnt the gradient and the normal parallel vectors?
no the gradient is parallel to the plane
If you found the N and have a point whats the problem?
hmmm.... whats the gradient of 0 = 2x -y +4
just trying to understand concepts :)
<2,-1,0> right?
is that perp or // to y=2x+4 ; z=0?
||
so the vector <2,-1>; whose slope is -1/2 is // with the plne y=2x+2; z=0?
(-1/2)*2=-1.....
u cant define a gradient vector for a line
i didnt; i defined a plane; hence the z=0
fine
bt m saying i think wt i did ws right
Do you guys know about green theorem?
i can tell :)
ive heard f it..nt studied it..
hey sorry..i confirmed..the gradient vector is normal to the surface..rly sorry
if we dot the gradient to a vector parallel to the plane y=2x+4; z=0, we will know if its perp or //
no i confirmed
g=<2,-1,0> v=<1, 2,0> -------- 2-2+0=0
yes m tellin u its normal to the surface
wt u were doing is right...i feel u alrdy know all this nd ur just testing us out
;) gotta keep entertained ya know lol
mean guy
id give you another medal if i could ;)
wts stopping u??
the only option available to me is the undo lol
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