Question

A current is defined as i(t)=2e^(-t/3)u(t) .What is the total area under the curve for 0 15 years ago

Answer 1

let v = (-t/3) I'm assuming that u(t) is dt, but if it is another function then that eq would be the area under a surface. dv =-(1/3). the area under i(t) =-6* integral e^vdv = -6e^(-t/3), then sub in your limit values to get your answer

Answer 2

My possible answers are 2/3, 2,5 and 6.Which one you think should be correct? Thank you!

Answer 3

it looks like it should be -6, but that is not an option. I can't call it.