Question

i know it seems long but it the info being given :S
please help, thanks :)

A branching plant has stems, nodes, leaves and buds.
-there are 7 leaves at each node and at each node, 2 new stems grow. at the end of each final stem, there is a bud

one plant with 3 stages of nodes has 15 stems, 7 nodes, 49 leaves and 8 buds.

qs: how do i show that the number of leaves on one of those plants with n stages of nodes there are?

a formula given is 7(2^n-1)

thanks :)

Answer 1

oh pretty long

Answer 2

i kno, but its the info

Answer 3

srry this s damn complicated but still i l think n when i cm up with an ans i wl tel u

Answer 4

its alright thanks tho sweetznchillz,
at least you bothered to try :)

Answer 5

ok well looks like you have the formula already
this might help you understand where it comes from
there is an original bud which yields a stem which yields a node.
This node produces 1 bud, 2 stems and 7 leaves (stage 1)
those 2 stems each produce a node which produce 1 bud,2 stems and 7 leaves
this is stage 2 and so on
Leaves diagram: 3 stages 49 leaves

7
7
7
7
7
7
7

Answer 6

so for that answer i have to draw something similar to this???

Answer 7

im not sure, do they want you to use the formula to answer a question or do you have to describe the whole process

Answer 8

well the actual qs says: show that the number of leaves on one of these plants with n stages of nodes is 7(2^n-1)

Answer 9

ok then yes use the diagram
notice each stage can be represented as power of 2
stage 1: 2^0
stage2: 2^1
stage 3: 2^2
sum = 2^3 - 1

Answer 10

ok thanks you

Answer 11

no problem

Answer 12

:)