Question

48x^2+72x+9 (factor completely)

Answer 1

So far I have 3(16x^2 + 24x +3)

Answer 2

now let's look to see if 16x^2+24x+3 is factorable
a*c=16*3
find two factors of a*c that add up to be b
b=24
if there are no factors of a*c, then you say that is far as it can be factored over the integers
48
16*3
8*6
2*24
4*12
can you think any two factors of 48 that add up to be 24

Answer 3

we are done since this not factorable over the integers
your answer is 3(16x^2+24x+3)

Answer 4

oh, well thank you :)