Question

3y^2+5y=2

Answer 1

3y^2+5y-2=0
(3y-1)(y+2)

Answer 2

im confused how did you get -2 in the equation?

Answer 3

You subtract 2 from each side of the equation which then gives you a -2 on the left hand side of the equation and zero on the right hand side of the equation. Once you do this, you can then factor the equation.

Answer 4

ooohh! okay thanks!

Answer 5

would the answer be y=1/3 and -2?

Answer 6

You're welcome. Hopefully, you understood what I did. Yes, y=1/3 and -2.

Answer 7

so for 4m^2 -100=0 would we do the same thing?

Answer 8

Basically, you would do the same thing. The factor in this problem would be:
(2m-10)(2m+10) and m=5 and -5.

Answer 9

5x^2=40 this one were having alot of trouble on

Answer 10

5x^2 - 40 = 0

5(x^2-8) x=+- 2sqrt(2) ??

Answer 11

What you can do is to divide both sides by 5 and you get:

x^2=8
x=square root of 8=+/- square root (4)(2)=+/-2(square root 2)

Answer 12

\[\sqrt{8} =+/-(4) (2)=+/-2\sqrt{2}\]

Answer 13

is that how you write it?

Answer 14

im so confused

Answer 15

im so confused

Answer 16

To be completely correct you should put a +/- in front of square root 8 and use the same symbol for the square roots of 4 and 2. Otherwise, you are correct. What is the confusion?