Question

if you want to find the velocity function of a problem would you just take the 1st derivative of the original equation? for ex. s(t)=-16t^2-64t+512?

Answer 1

velocity is the derivative of position; yes the change of distance with respect to time/parameter

Answer 2

yeah
ds/dt = v

Answer 3

ok now my next question is when you are asked to find the acceleration of an object how would you do that? after finding the 1st derivative/velocity function?

Answer 4

differejntiate it again

Answer 5

a=dv/dt so a = d2v/dv2

Answer 6

so i should take the derivative of the velocity function?

Answer 7

what is curvature :)

Answer 8

the change in direction with respect to distance :)

Answer 9

no its the beauty of jennifer aniston..lol

Answer 10

yeah a=dv/dt

Answer 11

does your s(t) there indicate position of speed?

Answer 12

position as a function of time

Answer 13

the derivative of that function will tell you the speed it is going at any given position in time then

Answer 14

yea the reason why im asking this is because my professor gave us a question like this a while back and he asked for the velocity function, and then the acceleration. i got the velocity function no problem but then messed up and got the acceleration wrong. so just to clarify (velocity function = 1st derivative of original function, acceleration function = derivative of the velocity function?) thanks for all the help i really appreciate it

Answer 15

yeah its right

Answer 16

the derivative of velocity as part of acceleration.... if you do vectors

Answer 17

a = d^2s/dt^2.<T> + k(ds/dt)^2<N>

Answer 18

ok thanks everyone, im sure i will have a few more questions as this study session progressively gets more intense!