">A doctor who is treated a heart patient wants to presicribe medication to lowere the patients blood pressure. The body's reaction to this medication is a function of the dose admininistered. If the patient takes x milliters of the medication, his blood pressure should decrease by r=f(x) points where f(x)=3x^2-1/3x^3 How much should the patients blood pressure drop if he takes 2 milliieters of medication which i got 9.333 What is the maximum drop in blood pressure that can be achieved with this medication ?
For the first part, just substitute 2 for x and solve. For the second part, derive and set equal to zero, solve.
sii it would be 3(2)^2-1/3(2)^3=0
so it would be like 3(2)^2-1/3(2)^3=0
They're separate parts. First you solve for x=2 and then set the derivative to zero and solve to find the dosage that gives the maximum.
Once you find the dosage, you can out that in the original equation to ge the maximum drop in pressure.
can u show please
please
like how do u solve for x=2
r u there
Sure. \[F(2)=(3(2^{2}))\div(3(2^{3})) = 12/24 = 1/2\] Which gives us the points that he dropped by taking 2 mL of medication. This is how Hurons the max: \[F'(x)=[6x](3x ^{3}) - (3x ^{2}-1)[9x2] \div (3x ^{3})^{2}\] Setting that equal to zero, we get x=+-1. We know it can't be negative 1 because you can't give negative medicine, so plug in one and solve to get 2/3.
plug in 1 where
for what values of x make sencefor this function
and use interval notation
Find the first three terms in asending powers. 1-2x^2-x^4)(4+x^2-2x^4)
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