Is there another way to find the flux of the gradient of a scalar field through a shape than just taking the line integral for a vector field?

Question

amistre64 · Answer

thats was going to be my next chapter that i read to the kids for a bedtime story :)

anonymous · Answer

The function i have gives me an unsolvable integral when i use a line integral to find the flux of the gradient..

amistre64 · Answer

what does flux of a gradient mean; i know what a gradient is; but flux?

amistre64 · Answer

sounds like soldering :)

anonymous · Answer

im given a scaler field im told to find the gradient and integrate it around a shape

anonymous · Answer

the gradient that is.

amistre64 · Answer

whats the function?

amistre64 · Answer

im gonna read vector fields tonight; i hope its steamy ;)

anonymous · Answer

xe^(yz)

my shape is r(t)=<-2rcos(t),rcos(t),2sqrt(2)sin(t)>
t is between 0 and pi and my r is 2

amistre64 · Answer

Ok; the gradient should be the derivatives of your function in vector format..right?

amistre64 · Answer

gF(x,y,z) = <dF/dx, dF/dy, dF/dz> right?

anonymous · Answer

yeah

anonymous · Answer

i cant take the strait line integral and stokes doesnt work because the curl of the grad is zero

amistre64 · Answer

gF = <e^(yz),zx.e^(yz),yx.e^(yz)> the gradient vector right?

anonymous · Answer

yup

amistre64 · Answer

thats the extent of my abilities with that :)

anonymous · Answer

...

amistre64 · Answer

what is a flux?

anonymous · Answer

you cant help me

amistre64 · Answer

prolly not :)....give me a week ;)

anonymous · Answer

maybe a little longer

anonymous · Answer

No he's taking the same class you are (calc 3) so he'll probably be covering this later in the term

anonymous · Answer

anonymous · Answer

im taking vectors

anonymous · Answer

didnt cover this in calc 3

anonymous · Answer

really? It was covered in my 3rd semester calc class along with surface integrals, etc. Stoke's, Green's, etc

anonymous · Answer

flux but not this indepth of line integral theory