Need a little help--Instantaneous velocity: (derivatives) s=8t(squared)-10t+6; t=5. any help?,Thanks
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OpenStudy (anonymous):
Just use the sum rule. The derivative of a sum is the sum of the derivatives of each term.
myininaya (myininaya):
s'=2*8t-10
s'(5)=16(5)-10
OpenStudy (anonymous):
so s=156?
OpenStudy (anonymous):
No, s'(5) = 156
myininaya (myininaya):
s'(5)=80-10=70
did i miss something?
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OpenStudy (anonymous):
yeah, it's 70
OpenStudy (anonymous):
I didn't check his arithmetic. In anycase, this is the trouble with just solving people's problems myininaya. They don't understand what you did, so they don't understand the answer, or how to do it again next time.
OpenStudy (anonymous):
can you take it step by step for me ? now I am missing something , Thanks
myininaya (myininaya):
do you know how to find the derivative?
OpenStudy (anonymous):
yes
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myininaya (myininaya):
what is s' = then?
OpenStudy (anonymous):
Prime
myininaya (myininaya):
what is s'=______________?
OpenStudy (anonymous):
oh - i got 156
myininaya (myininaya):
the derivative of 8t^2 is?
the derivative of 10t is?
the derivative of constant is?
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myininaya (myininaya):
no clown i'm asking what is s'
not what s' at some number is
OpenStudy (anonymous):
16t,10,0
myininaya (myininaya):
so s'=16t+10+0=16t+10
myininaya (myininaya):
oops s'=16t-10 i forgot the minus in the problem
myininaya (myininaya):
so what is s' at t=5
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OpenStudy (anonymous):
Man your rough! but you make me think! ---- Thanks
myininaya (myininaya):
i'm rough lol
myininaya (myininaya):
do you get 70 now?
OpenStudy (anonymous):
Hold on Im old!
OpenStudy (anonymous):
yes, Thank you , Wow ! LOL
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myininaya (myininaya):
you really got it?
ok what's the instanteous velocity of s=t^4-6^2+3 at t=3
OpenStudy (anonymous):
Oh and by the way I am a real clown, A Shriner Clown
myininaya (myininaya):
s=t^4-6t^2+3
myininaya (myininaya):
cool. lol
OpenStudy (anonymous):
s=45?
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myininaya (myininaya):
what is s' ?
OpenStudy (anonymous):
um, ok im lost ! Help!!
myininaya (myininaya):
we want to find the instanteous velocity of s=t^4-6t^2+3 at t=3
finding velocity means we need to find the derivative of s
s' denotes the derivative
first let's break this up
what is the derivative of t^4?
what is the derivative of -6t^2?
what is the derivative of 3?
OpenStudy (anonymous):
3t,12t,0
OpenStudy (anonymous):
-12t oops
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myininaya (myininaya):
derivative of t^4 is 4*t^3
i used the power rule
everything else you got right
so 2/3 is passing
OpenStudy (anonymous):
you funny and yes you are right about the first answer , you are making me think faster than normal! and making me nervous! I do not want to come off to you as a complete rock!
myininaya (myininaya):
i'm sorry
myininaya (myininaya):
lol take as much time as you need
OpenStudy (anonymous):
ok, Thanks! Just wish sometimes I was better at this stuff, like you- I love smart math people!
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myininaya (myininaya):
clowns are cool too
myininaya (myininaya):
let's put all the terms of s' together so
s'=?
OpenStudy (anonymous):
ok, hold, please
myininaya (myininaya):
k
OpenStudy (anonymous):
s=96
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myininaya (myininaya):
i don't think thats right
and like polak said before its s'(3)=96
tell me what s' is first
myininaya (myininaya):
s'(t)=
OpenStudy (anonymous):
4(3)^3-12+3 Right?
myininaya (myininaya):
s'(3)=4(3)^3-12(3)
myininaya (myininaya):
remember we said the derivative of t^4 is 4t^3
the derivative of -6t^2 is -12t
the derivative of 3 is 0
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OpenStudy (anonymous):
OK!!!!! 3 is prime right?
myininaya (myininaya):
yes 3 is prime
since 3 is a constant, its slope is zero, and since its slope is zero then the derivative of 3 is zero
OpenStudy (anonymous):
we had a- 6t in the original problem? sorry my Bad yes we did, SO SORRY!
OpenStudy (anonymous):
Hold on
OpenStudy (anonymous):
s= 144+ 3?
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OpenStudy (anonymous):
or just 144?
OpenStudy (amistre64):
ok...so whats our question?
myininaya (myininaya):
s=t^4-6t^2+3
find velocity at t=3
i think hes getting mixed up on where things go
OpenStudy (amistre64):
so clown; you say you can find a derivative; right?
OpenStudy (anonymous):
I thought so, guess not
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OpenStudy (amistre64):
go ahead and give it a shot, i wanna see what you are doing
OpenStudy (amistre64):
what is the derivative of:
t^4 -6^t +3 ??
OpenStudy (anonymous):
Here is my problem..... s=8t^2 -10t +6; t=5
OpenStudy (amistre64):
ok....lets work with 8t^2 -10t +6; what do you think the derivative should look like?
OpenStudy (anonymous):
16t- 10 + 6
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OpenStudy (amistre64):
very close; the first and second terms are good; that last terms should be a 0 tho. do you know why?
OpenStudy (anonymous):
because there is no constant?
OpenStudy (amistre64):
does 6 = 6 t^0 ? and if so; how would you derive:
6 t^0?
OpenStudy (anonymous):
Yes , due to the fact of the power 0
OpenStudy (amistre64):
good;
then lets rewrite this in terms you can see :)
8t^2 -10t +6t^0; now derive that for me...
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OpenStudy (anonymous):
16t-10+6
OpenStudy (amistre64):
16t is good;
-10 is excellent.
but 6 is wrong, you didnt derive it the same way you did the others ...why not?
derive 6t^0. in exactly the same way as you did the others. what do we get?
OpenStudy (anonymous):
0
OpenStudy (amistre64):
that is correct:)
so would you agree that our derivative is then:
16t-10 ?
OpenStudy (anonymous):
Yes
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OpenStudy (amistre64):
ds
-- = 16t-10 very good; now when t=5, what does this equal?
dt
OpenStudy (anonymous):
70!! I got it and you did not leave me at the train depot!!! YEA!!!!!
OpenStudy (amistre64):
yay!!! :)
OpenStudy (anonymous):
Thaank you very much!!!
OpenStudy (amistre64):
youre welcome :)
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